问题:
俄罗斯方块源代码
C语言的，环境是codeblocks
推荐答案:
#include <stdlib.h>
#include <graphics.h>
#include <bios.h>
#define mDRAW 5
#define mLINE 6
#define mADOWN 7
#define mGEN 8
#define mLEFT 75
#define mRIGHT 77
#define mSPACE 57
#define mDOWN 80
#define mESC 1
#define TIMEINT 2
#define MAXX 9
#define MAXY 30
#define BACKCOLOR BLACK
#define WINX 50
#define WINY 470
#define GAP 6
#define AREAX (WINX+GAP)
#define AREAY (WINY-GAP)
#define BOXW 15
int oldarea[MAXY+1][MAXX];
int area[MAXY+1][MAXX];
int actW,actH,actX,actY;
int curX,curY,curColor,curW,curH;
int newX,newY,newColor,newW,newH;
int active;
int box[4][4];
int FORCOLOR;
int MESSAGE;
int BOX[7][4][4]={
{
{1,1,1,1},
{0,0,0,0},
{0,0,0,0},
{0,0,0,0}
},{
{1,1,1,0},
{1,0,0,0},
{0,0,0,0},
{0,0,0,0}
},{
{1,1,1,0},
{0,0,1,0},
{0,0,0,0},
{0,0,0,0}
},{
{1,1,1,0},
{0,1,0,0},
{0,0,0,0},
{0,0,0,0}
},{
{1,1,0,0},
{0,1,1,0},
{0,0,0,0},
{0,0,0,0}
},{
{0,1,1,0},
{1,1,0,0},
{0,0,0,0},
{0,0,0,0}
},{
{1,1,0,0},
{1,1,0,0},
{0,0,0,0},
{0,0,0,0}
}
};
void init();
void draw();
int genBox();
int getKey();
void lineFull();
int moveLeft();
int moveRight();
int moveDown();
int rotate();
int getW();
int getH();
void clearOldBox();
void putNewBox();
int collisionRotate(int box[][4]);
void getMessage();
void dispatchMessage();
int timeCome();
void fallDown();
int gameOver();
main()
{
int i;
init();
do
{
getMessage();
dispatchMessage();
}
while(!gameOver());
getch();
closegraph();
}
void getMessage()
{
if(MESSAGE) return;
if(timeCome())
{
MESSAGE=mADOWN;
return;
}
if(bioskey(1))
{
MESSAGE=bioskey(0)>>8;
return;
}
}
void dispatchMessage()
{
switch(MESSAGE)
{
case mLEFT: moveLeft();break;
case mRIGHT: moveRight();break;
case mADOWN: moveDown();break;
case mSPACE: rotate();break;
case mDOWN: fallDown(); break;
case mDRAW: draw();break;
case mLINE: lineFull();break;
case mGEN: genBox();break;
case mESC: closegraph(); exit(0);
default: MESSAGE=0;
}
}
void fallDown()
{
while(active)
{
moveDown(); draw();
}
MESSAGE=mLINE;
}
int timeCome()
{
static long tm, old;
tm=biostime(0,tm);
if(tm-old<TIMEINT) return 0;
else
{
old=tm; return 1;
}
}
void init()
{
int i,j,x1,y1,x2,y2;
int driver=DETECT, mode=0;
randomize();
registerbgidriver(EGAVGA_driver);
initgraph(&driver,&mode,&quot;&quot;);
cleardevice();
setfillstyle(SOLID_FILL,BLUE);
bar(0,0,639,479);
x1=AREAX;
y1=AREAY-BOXW*MAXY;
x2=AREAX+MAXX*BOXW;
y2=AREAY;
rectangle(--x1,--y1,++x2,++y2);
setfillstyle(SOLID_FILL,BLACK);
bar(++x1,++y1,--x2,--y2);
y1=AREAY-MAXY*BOXW; y2=AREAY;
setcolor(DARKGRAY);
for(i=0;i<MAXX;i++)
{
x1=AREAX+i*BOXW;
line(x1,y1,x1,y2);
}
x1=AREAX; x2=x1+MAXX*BOXW;
for(j=0;j<MAXY;j++)
{
y1=AREAY-j*BOXW;
line(x1,y1,x2,y1);
}
for(j=0;j<MAXY;j++)
for(i=0;i<MAXX;i++)
area[j]=oldarea[j]=0;
actX=0; actY=0; actW=MAXX-1; actH=MAXY-1;
draw();
MESSAGE=mGEN;
}
int genBox()
{
int i,j,boxidx;
boxidx=random(7); FORCOLOR=random(7)+1;
for(j=0;j<4;j++)
for(i=0;i<4;i++)
box[j]=BOX[boxidx][j];
curW=getW(); curH=getH();
curX=(MAXX+curW)/2;
if(curX+curW>=MAXX)curX=MAXX-1-curW;
curY=MAXY-1-curH;
newX=curX; newY=curY; actX=curX;actY=curY;
actW=newW=curW; actH=newH=curH;
active=1;
if(collision(box)) return 0;
putNewBox();
draw(); MESSAGE=0;
return 1;
}
void lineFull()
{
int row,col, rowEnd,full,i,j;
rowEnd=newY+newH;
if(rowEnd>=MAXY-1) rowEnd=MAXY-2;
for(row=newY; row<=rowEnd;)
{
full=1;
for(col=0;col<MAXX;col++)
if(!area[row][col]){full=0; break;}
if(!full){++row; continue;}
for(j=row; j<MAXY-1;j++)
for(i=0;i<MAXX;i++)
area[j]=area[j+1];
actX=0;actY=row; actW=MAXX-1; actH=MAXY-1-row;
draw(); rowEnd--;
}
MESSAGE=mGEN;
}
void draw()
{
int row,col,x1,y1,x2,y2;
for(row=actY;row<=actY+actH;row++)
for(col=actX;col<=actX+actW;col++)
if(area[row][col]!=oldarea[row][col])
{
if(area[row][col]==0)
setfillstyle(SOLID_FILL,BACKCOLOR);
else
setfillstyle(SOLID_FILL,FORCOLOR);
x1=AREAX+col*BOXW; x2=x1+BOXW;
y1=AREAY-(row+1)*BOXW; y2=y1+BOXW;
bar(++x1,++y1,--x2,--y2);
oldarea[row][col]=area[row][col];
}
MESSAGE=0;
}
int moveLeft()
{
newX=curX-1; clearOldBox();
if(collision(box))
{
newX=curX;
putNewBox();
MESSAGE=0;
return 0;
}
putNewBox();
actW=curW+1; actX=curX=newX;
MESSAGE=mDRAW;
return 1;
}
int moveRight()
{
newX=curX+1; clearOldBox();
if(collision(box))
{
newX=curX;
putNewBox();
MESSAGE=0;
return 0;
}
putNewBox();
actW=curW+1; actX=curX; curX=newX;
MESSAGE=mDRAW;
return 1;
}
int moveDown()
{
int i,j;
newY=curY-1;
clearOldBox();
if(collision(box))
{
newY=curY;
putNewBox();
active=0;
MESSAGE=mLINE;
return 0;
}
putNewBox();
actH=curH+1; actY=newY; curY=newY;
MESSAGE=mDRAW;
return 1;
}
int rotate()
{
int newBox[4][4];
int i,j;
clearOldBox();
for(j=0;j<4;j++)
for(i=0;i<4;i++)
newBox[j]=0;
for(j=0;j<4;j++)
for(i=0;i<4;i++)
newBox[curW-i][j]=box[j];
newW=curH; newH=curW;
if(collisionRotate(newBox))
{
newW=curW; newH=curH; newX=curX; newY=curY;
putNewBox();
MESSAGE=0;
return 0;
}
for(j=0;j<4;j++)
for(i=0;i<4;i++)
box[j]=newBox[j];
putNewBox();
actH=newH>curH? newH:curH;
actW=curX+actH-newX;
actX=newX; actY=newY; curX=newX;
curY=newY; curW=newW; curH=newH;
MESSAGE=mDRAW;
return 1;
}
int getW()
{
int i,j;
for(i=3;i>0;i--)
for(j=0;j<4;j++)
if(box[j]) return i;
return 0;
}
int getH()
{
int i,j;
for(j=3;j>0;j--)
for(i=0;i<4;i++)
if(box[j]) return j;
return 0;
}
void clearOldBox()
{
int i,j;
for(j=0;j<=curH; j++)
for(i=0;i<=curW; i++)
if(box[j])
area[curY+j][curX+i]=0;
}
void putNewBox()
{
int i,j;
for(j=0;j<=newH;j++)
for(i=0;i<=newW;i++)
if(box[j])
area[newY+j][newX+i]=FORCOLOR;
}
int collision(int cbox[][4])
{
int i,j;
if(newX<0) return 1;
if(newX+newW>=MAXX) return 1;
if(newY<0) return 1;
for(j=0;j<=newH;j++)
for(i=0;i<=newW;i++)
if(area[newY+j][newX+i]&&cbox[j]) return 1;
return 0;
}
int collisionRotate(int cbox[][4])
{
int i,j;
if(newX+newW>=MAXX) newX=MAXX-1-newW;
if(newY+newH>=MAXY) newY=MAXY-1-newH;
if(collision(cbox)) return 1;
for(i=0;i<=newW;i++)
for(j=0;j<=newH;j++)
if(area[newY+j][newX+i])
{
newX-=newW-i+1; goto L;
}
L: return collision(cbox);
}
int gameOver()
{
if(!active &&(curY+curH>MAXY-3)) return 1;
else return 0;
}
其他答案:
自已要先有一个构思，再看看网上的实现逻辑，再比较一下体会一下
其他答案:
俄罗斯方块源码我见过一些，基本都是利用一个二维数组来实现的！~
其他答案:
你自己探索吧！
其他答案:
http://blog.csdn.net/cug_wx/article/details/8546240 这个链接里有，如果没有那我也没办法了
其他答案:
你觉得的呢，你自己也应该学习一下，自己体会一下就知道了 |
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